2.2 KiB
2.2 KiB
181.超过经理收入的员工
2022-08-10 22:05:28
SQL架构
Create table If Not Exists Employee
(
id int,
name varchar(255),
salary int,
managerId int
);
Truncate table Employee;
insert into Employee (id, name, salary, managerId)
values ('1', 'Joe', '70000', '3');
insert into Employee (id, name, salary, managerId)
values ('2', 'Henry', '80000', '4');
insert into Employee (id, name, salary, managerId)
values ('3', 'Sam', '60000', 'None');
insert into Employee (id, name, salary, managerId)
values ('4', 'Max', '90000', 'None');
题
表:Employee
+-------------+---------+
| Column Name | Type |
+-------------+---------+
| id | int |
| name | varchar |
| salary | int |
| managerId | int |
+-------------+---------+
Id是该表的主键。
该表的每一行都表示雇员的ID、姓名、工资和经理的ID。
编写一个SQL查询来查找收入比经理高的员工。
以 任意顺序 返回结果表。
查询结果格式如下所示。
示例 1:
**输入:**
Employee 表:
+----+-------+--------+-----------+
| id | name | salary | managerId |
+----+-------+--------+-----------+
| 1 | Joe | 70000 | 3 |
| 2 | Henry | 80000 | 4 |
| 3 | Sam | 60000 | Null |
| 4 | Max | 90000 | Null |
+----+-------+--------+-----------+
**输出:**
+----------+
| Employee |
+----------+
| Joe |
+----------+
**解释:** Joe 是唯一挣得比经理多的雇员。
Related Topics
- 数据库
解
SELECT a.Name AS 'Employee'
FROM Employee AS a,
Employee AS b
WHERE a.ManagerId = b.Id
AND a.Salary > b.Salary;
SELECT a.Name AS 'Employee'
FROM Employee a,
Employee b
WHERE a.ManagerId = b.Id
AND a.Salary > b.Salary;
SELECT a.NAME AS Employee
FROM Employee AS a
JOIN Employee AS b
ON a.ManagerId = b.Id
AND a.Salary > b.Salary;
SELECT a.NAME AS Employee
FROM Employee a
JOIN Employee b
ON a.ManagerId = b.Id
AND a.Salary > b.Salary;
不加AS
的快一点好像。