my_leetcode/sql/q0181.md

181.超过经理收入的员工

2022-08-10 22:05:28

SQL架构

Create table If Not Exists Employee
(
    id        int,
    name      varchar(255),
    salary    int,
    managerId int
);
Truncate table Employee;

insert into Employee (id, name, salary, managerId)
values ('1', 'Joe', '70000', '3');

insert into Employee (id, name, salary, managerId)
values ('2', 'Henry', '80000', '4');

insert into Employee (id, name, salary, managerId)
values ('3', 'Sam', '60000', 'None');

insert into Employee (id, name, salary, managerId)
values ('4', 'Max', '90000', 'None');

题

表：Employee

+-------------+---------+
| Column Name | Type    |
+-------------+---------+
| id          | int     |
| name        | varchar |
| salary      | int     |
| managerId   | int     |
+-------------+---------+
Id是该表的主键。
该表的每一行都表示雇员的ID、姓名、工资和经理的ID。

编写一个SQL查询来查找收入比经理高的员工。

以 任意顺序 返回结果表。

查询结果格式如下所示。

示例 1:

**输入:** 
Employee 表:
+----+-------+--------+-----------+
| id | name  | salary | managerId |
+----+-------+--------+-----------+
| 1  | Joe   | 70000  | 3         |
| 2  | Henry | 80000  | 4         |
| 3  | Sam   | 60000  | Null      |
| 4  | Max   | 90000  | Null      |
+----+-------+--------+-----------+
**输出:** 
+----------+
| Employee |
+----------+
| Joe      |
+----------+
**解释:** Joe 是唯一挣得比经理多的雇员。

Related Topics

• 数据库

解

SELECT a.Name AS 'Employee'
FROM Employee AS a,
     Employee AS b
WHERE a.ManagerId = b.Id
  AND a.Salary > b.Salary;

SELECT a.Name AS 'Employee'
FROM Employee a,
     Employee b
WHERE a.ManagerId = b.Id
  AND a.Salary > b.Salary;

SELECT a.NAME AS Employee
FROM Employee AS a
         JOIN Employee AS b
              ON a.ManagerId = b.Id
                  AND a.Salary > b.Salary;

SELECT a.NAME AS Employee
FROM Employee a
         JOIN Employee b
              ON a.ManagerId = b.Id
                  AND a.Salary > b.Salary;

不加AS的快一点好像。